Problem 10: Assuming that the stationary wave is not limited by the string length of 320 mm ( AB ) the wavelength of the standing wave would be CB x 2 = 240 mm x 2 = 480 mm. This is because CB only represents half a cycle of the total waveform.
I'm going to throw some easier ones in from time to time, mixed in amongst harder ones. You just need to keep an eye on the thread
Problem 10 Attempt 2: The note played at AB is 780 Hz. The wavelength of AB = 1/780 Hz = 1.282 mm. The ratio of AB / CB = 240 mm / 320 mm = 0.75 ( Wavelength of AB ) x AB / CB = .9615 mm <-- which is the wavelength at CB. This can be confirmed because a smaller wavelength increases the frequency of the note. 1 / .9615 mm = 1040 Hz You can go further, as you mention AB is the overtone, and find the fundamental frequency which is 1040 Hz - 780 Hz = 260 Hz
PROBLEM 8 Answer -- Zn^+2(aq) + 2e^- ---> Zn(s) The Zinc ion is the strongest reducing agent because it has a greater tendency to lose electrons. Proof-- I'm a chemist slut. JK i know this crap cause chemistry classroom .
"state why in terms of electrode potential" Using the table provided, how did you know that it was the strongest reducing agent?
No balls, can't do it. "When a low molar concentration aqueous solution containing ethanedioate ions combines with to a solution of aqueous copper(II) ions, there is a substitution reaction. In this reaction four water molecules are replaced and this results in a new complex. Using your favorite tools (better be ms-paint m8), draw a diagram showing the bonds to the Copper ions, including bond angles, and correct planar representation."